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Tensors

Einstein’s Summation Convention

Get the pdf here: summation (pdf)

Understanding Gravitation and all kinds of modern physics requires a working knowledge of Einstein’s summation convention.

And here is the truth behind the word itself: a tensor is a machine that eats several vectors and returns a number, and is linear in each one it eats.

Scalars, vectors and matrices are all tensors. They’re the first three rungs of one ladder.

The core idea, in plain words

A Linear Operator is linear in one input. A multilinear map is linear in each of several inputs separately, holding the others fixed. The dot product is the classic example: ⟨u,v⟩\langle u, v \rangle is linear in uu and linear in vv. That makes it a tensor of rank 2.

The rank (or order) is just how many slots the machine has:

Here is the point that separates a tensor from “a box of numbers”: its components must change in a specific way when you change coordinates, so that the machine itself stays the same. A tensor is a geometric fact; its components are just how that fact looks in your current coordinate system.

That’s exactly why physics loves them. If an equation between tensors is true in one coordinate system, it’s true in every coordinate system. The laws of nature can’t depend on how we draw our axes.

An everyday analogy: stress inside a block of jelly

Press on a block of jelly. At any point inside, if you imagine a tiny cut facing some direction, the jelly on one side pushes on the other with a force, which might point in a different direction from the cut. Input: a direction (the cut). Output: a force (a vector). That rule is linear, and with one more slot (ask “how much of that force along this direction?”) it becomes a rank-2 tensor, the stress tensor. Rotate your measuring axes and all nine numbers change, but the jelly is squeezed exactly the same.

A worked example: the summation convention in action

Einstein’s convention says: when an index appears once up and once down, sum over it. So

viwimeansv1w1+v2w2+v3w3. v^i w_i \quad\text{means}\quad v^1 w_1 + v^2 w_2 + v^3 w_3.

Take the metric of ordinary flat space, gij=1g_{ij} = 1 if i=ji = j, else 00. The squared length of a vector v=(3,4,12)v = (3, 4, 12) is

gijvivj=(3)2+(4)2+(12)2=169,∥v∥=13. g_{ij} v^i v^j = (3)^2 + (4)^2 + (12)^2 = 169, \qquad \|v\| = 13.

Two indices, two sums, nine terms, of which only three survive. Now switch to the spacetime of special Relativity, where (with units where light speed is 1) the metric is η=diag(−1,1,1,1)\eta = \mathrm{diag}(-1, 1, 1, 1). For an event 5 units away in time and 3 in space,

ημνxμxν=−52+32=−16. \eta_{\mu\nu} x^\mu x^\nu = -5^2 + 3^2 = -16.

Every observer, moving at any speed, computes the same −16-16. That invariant interval is the beating heart of relativity, and the tensor notation guarantees it.

A picture in words: the tensor product of two vectors

Take an arrow u=(1,2)u = (1, 2) and an arrow v=(3,4)v = (3, 4). Form every possible product of a component of uu with a component of vv and lay them out in a grid:

u⊗v=(1⋅31⋅42⋅32⋅4)=(3468). u \otimes v = \begin{pmatrix} 1 \cdot 3 & 1 \cdot 4 \\ 2 \cdot 3 & 2 \cdot 4 \end{pmatrix} = \begin{pmatrix} 3 & 4 \\ 6 & 8 \end{pmatrix}.

Picture it as a multiplication table. Every rank-2 tensor is a sum of tables like this. A table that is a single u⊗vu \otimes v has proportional rows; a general tensor needs several. In Quantum Mechanics, a two-particle state that is a single u⊗vu \otimes v is “unentangled”; one that needs a sum is entangled. Entanglement is literally “this tensor doesn’t factor.”

graph LR
  S["Rank 0: scalar"] --> V["Rank 1: vector vⁱ"]
  V --> M["Rank 2: gᵢⱼ"]
  M --> T["Rank 3+: Tᵢⱼₖ"]

Common misconceptions

How it connects

The truth revealed: a tensor is the part of a calculation that doesn’t care how you drew your axes.

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