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algebra

Vector Spaces

Here is the truth about vector spaces that no textbook says plainly enough: a vector is anything you can add to another of its kind and stretch by a number. That’s it. Arrows are just the most famous example.

Once you see that, functions, polynomials, sound waves and quantum states all turn out to be vectors.

The core idea, in plain words

Pick a Field FF of scalars (usually R\mathbb{R} or C\mathbb{C}). A vector space over FF is a set VV with:

satisfying the natural rules: c(u+v)=cu+cvc(u + v) = cu + cv, (c+d)v=cv+dv(c + d)v = cv + dv, (cd)v=c(dv)(cd)v = c(dv) and 1v=v1v = v.

Exactly the definition of a Module, with the ring promoted to a field. And that promotion buys a miracle: every vector space has a basis, a set of vectors such that every vector is a combination of them in exactly one way. The number of basis vectors is the same however you choose them, and it is called the dimension.

An everyday analogy: colours on a screen

Every colour your screen shows is a mix of red, green and blue light. “Add” two colours by adding their light; “scale” a colour by dimming or brightening it. Red, green and blue form a basis: every colour is a unique recipe of so much red, so much green, so much blue. Colour space is 3-dimensional. You could choose a different basis (cyan, magenta, yellow, say) and describe the same colours with different numbers, but you’d always need exactly three.

A worked example: polynomials as vectors

Let P2P_2 be all polynomials of degree at most 2 with real coefficients, a+bx+cx2a + bx + cx^2. Add two of them and you get another; multiply by a real number and you get another. So P2P_2 is a vector space.

A basis: {1,x,x2}\{1, x, x^2\}. The polynomial 3−2x+5x23 - 2x + 5x^2 has coordinates (3,−2,5)(3, -2, 5). So dim⁡P2=3\dim P_2 = 3, and P2P_2 behaves exactly like R3\mathbb{R}^3.

Now check a different basis: {1, 1+x, 1+x+x2}\{1,\ 1 + x,\ 1 + x + x^2\}. Write 3−2x+5x23 - 2x + 5x^2 in it:

3−2x+5x2=a⋅1+b(1+x)+c(1+x+x2). 3 - 2x + 5x^2 = a \cdot 1 + b(1 + x) + c(1 + x + x^2).

Matching x2x^2: c=5c = 5. Matching xx: b+c=−2b + c = -2, so b=−7b = -7. Matching constants: a+b+c=3a + b + c = 3, so a=5a = 5. New coordinates (5,−7,5)(5, -7, 5). Same vector, different coordinates. The vector doesn’t care which basis you use; only its description changes.

And linear independence: are 1+x1 + x, 1−x1 - x and 22 independent? No: (1+x)+(1−x)−2=0(1 + x) + (1 - x) - 2 = 0. One of them is redundant, and together they only span a 2-dimensional piece of P2P_2.

A picture in words: a flat sheet through the origin

Stand in ordinary 3D space. A subspace is a flat thing through the origin: the origin alone (dimension 0), a line through it (dimension 1), a plane through it (dimension 2), or everything (dimension 3). A plane that misses the origin is not a subspace, because it doesn’t contain 0\mathbf{0}, and adding two of its vectors pushes you off it.

Two arrows not on the same line span a plane: every point on the plane is “so much of the first plus so much of the second”, like coordinates on a slanted sheet of graph paper.

graph LR
  S["Spanning set: reaches everything"] --> B["Basis: spanning AND independent"]
  I["Independent set: no redundancy"] --> B
  B --> D["Dimension = size of any basis"]

Common misconceptions

How it connects

The truth revealed: a vector is not an arrow. It is anything that adds and scales, and arrows are only the first thing that does.

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